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3h^2=50
We move all terms to the left:
3h^2-(50)=0
a = 3; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·3·(-50)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*3}=\frac{0-10\sqrt{6}}{6} =-\frac{10\sqrt{6}}{6} =-\frac{5\sqrt{6}}{3} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*3}=\frac{0+10\sqrt{6}}{6} =\frac{10\sqrt{6}}{6} =\frac{5\sqrt{6}}{3} $
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